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thermodynamics

1. Introduction

1.1 Scope of Thermodynamics

Thermodynamics is the branch of physics that deals with heat, work, temperature, and their relation to energy, entropy, and the physical properties of matter. It provides a macroscopic description of systems without requiring detailed knowledge of microscopic constituents.

Unlike classical mechanics, which describes individual particle trajectories, thermodynamics operates on aggregate quantities — pressure, volume, temperature, and internal energy — that characterise bulk matter.

1.2 Macroscopic vs Microscopic Perspectives

Classical thermodynamics is purely macroscopic: it relates observable quantities through empirical laws (the four laws of thermodynamics) without reference to atoms or molecules.

Statistical mechanics provides the microscopic foundation: macroscopic thermodynamic quantities emerge as statistical averages over enormous numbers of microscopic states. The bridge between the two perspectives is given by Boltzmann”s entropy formula:

S=kBlnΩS = k_B \ln \Omega

where Ω\Omega is the number of accessible microstates.

1.3 Systems, Boundaries, and Processes

A thermodynamic system is the portion of the universe under study, separated from its surroundings by a boundary. Systems are classified by the nature of their boundary:

  • Open: Exchange of both matter and energy.
  • Closed: Exchange of energy but not matter.
  • Isolated: No exchange of matter or energy.

A thermodynamic process is a change of state of a system. Key processes include:

  • Isothermal: Constant temperature (dT=0dT = 0).
  • Adiabatic: No heat exchange (δQ=0\delta Q = 0).
  • Isobaric: Constant pressure (dp=0dp = 0).
  • Isochoric: Constant volume (dV=0dV = 0).

2. Zeroth and First Laws

2.1 The Zeroth Law and Temperature

Zeroth Law of Thermodynamics. If system AA is in thermal equilibrium with system BB, and system BB is in thermal equilibrium with system CC, then AA is in thermal equilibrium with CC.

This law establishes temperature as a well-defined property: all systems in mutual thermal equilibrium share the same temperature. It motivates the existence of temperature scales and thermometers.

The ideal gas temperature scale is defined by the ideal gas law, which experiments show is approached by all real gases in the low-density limit:

pV=nRTpV = nRT

where R=8.314  J mol1K1R = 8.314\;\text{J mol}^{-1}\text{K}^{-1} is the molar gas constant. The temperature in Kelvin is defined such that the triple point of water is exactly 273.16  K273.16\;\text{K}.

2.2 The First Law and Internal Energy

First Law of Thermodynamics. The change in internal energy of a system equals the heat added to the system minus the work done by the system:

dU=δQδWdU = \delta Q - \delta W

or equivalently (sign convention: work done on the system):

ΔU=QW\Delta U = Q - W

where ΔU\Delta U depends only on the initial and final states (it is a state function), while QQ and WW depend on the path taken.

2.3 Work and Heat

For a quasi-static process, the work done by an ideal gas expanding against an external pressure is:

δW=pdV\delta W = p\,dV

Other forms of work include:

δW=Edq(electrical),δW=γdA(surface tension),δW=MdB(magnetic)\delta W = -\mathcal{E}\,dq \quad \text{(electrical)}, \qquad \delta W = \gamma\,dA \quad \text{(surface tension)}, \qquad \delta W = -\mathbf{M} \cdot d\mathbf{B} \quad \text{(magnetic)}

Heat capacity relates heat input to temperature change:

C=δQdTC = \frac{\delta Q}{dT}

For ideal gases:

  • At constant volume: CV=f2nRC_V = \frac{f}{2}nR where ff is the number of degrees of freedom.
  • At constant pressure: Cp=CV+nRC_p = C_V + nR (Mayer’s relation).
  • The ratio: γ=Cp/CV=(f+2)/f\gamma = C_p/C_V = (f+2)/f.

2.4 Ideal Gas Processes

Isothermal expansion (T=constT = \text{const}): From pV=nRTpV = nRT and dU=0dU = 0 (ideal gas internal energy depends only on TT):

Q=W=nRTlnVfViQ = W = nRT \ln\frac{V_f}{V_i}

Adiabatic expansion (δQ=0\delta Q = 0): From the first law, dU=δW=pdVdU = -\delta W = -p\,dV. For an ideal gas this yields the adiabatic relation:

pVγ=const,TVγ1=constpV^\gamma = \text{const}, \qquad TV^{\gamma-1} = \text{const}

Isobaric expansion (p=constp = \text{const}):

W=p(VfVi),Q=nCp(TfTi)W = p(V_f - V_i), \qquad Q = nC_p(T_f - T_i)

Worked Example 2.1: Adiabatic Compression of a Monatomic Gas

A monatomic ideal gas (γ=5/3\gamma = 5/3) is compressed adiabatically from V1=10  LV_1 = 10\;\text{L}, T1=300  KT_1 = 300\;\text{K} to V2=2  LV_2 = 2\;\text{L}.

T2=T1(V1V2)γ1=300×52/3=300×2.924=877  KT_2 = T_1 \left(\frac{V_1}{V_2}\right)^{\gamma - 1} = 300 \times 5^{2/3} = 300 \times 2.924 = 877\;\text{K}

W=nR(T1T2)γ1=nR(300877)2/3=32nR×577W = \frac{nR(T_1 - T_2)}{\gamma - 1} = \frac{nR(300 - 877)}{2/3} = -\frac{3}{2}nR \times 577

For n=1  moln = 1\;\text{mol}: W=32(8.314)(577)=7.19  kJW = -\frac{3}{2}(8.314)(577) = -7.19\;\text{kJ} (negative = work done on the gas).

3. Second Law and Entropy

3.1 The Second Law: Statements

Clausius statement. Heat cannot spontaneously flow from a colder body to a hotter body.

Kelvin–Planck statement. No process is possible whose sole result is the complete conversion of heat into work.

Both statements are equivalent — a violation of one implies a violation of the other.

3.2 The Carnot Cycle

The Carnot cycle is the most efficient heat engine operating between two temperatures. It consists of four reversible stages:

  1. Isothermal expansion at THT_H: absorb heat QHQ_H from the hot reservoir.
  2. Adiabatic expansion: temperature drops from THT_H to TCT_C.
  3. Isothermal compression at TCT_C: reject heat QCQ_C to the cold reservoir.
  4. Adiabatic compression: temperature rises from TCT_C to THT_H.

The Carnot efficiency is:

ηCarnot=1TCTH\eta_{\text{Carnot}} = 1 - \frac{T_C}{T_H}

This is the maximum possible efficiency for any heat engine operating between THT_H and TCT_C.

3.3 Entropy

Definition (Clausius entropy). For a reversible process:

dS=δQrevTdS = \frac{\delta Q_{\text{rev}}}{T}

Entropy is a state function: its change depends only on initial and final states.

Second Law (entropy form). For any process, the total entropy of an isolated system never decreases:

ΔStotal0\Delta S_{\text{total}} \geq 0

with equality if and only if the process is reversible.

For an ideal gas undergoing a reversible process:

ΔS=nCVlnTfTi+nRlnVfVi\Delta S = nC_V \ln\frac{T_f}{T_i} + nR \ln\frac{V_f}{V_i}

3.4 Entropy of Mixing

When nAn_A moles of ideal gas AA and nBn_B moles of ideal gas BB, initially separated, are allowed to mix at the same TT and pp:

ΔSmix=nARlnxAnBRlnxB\Delta S_{\text{mix}} = -n_A R \ln x_A - n_B R \ln x_B

where xA=nA/(nA+nB)x_A = n_A/(n_A + n_B) is the mole fraction. This is always positive (since xi<1x_i < 1), reflecting the irreversibility of spontaneous mixing.

3.5 The Clausius Inequality

For any cyclic process:

δQT0\oint \frac{\delta Q}{T} \leq 0

with equality for reversible cycles. This generalises the second law: δQ/T\delta Q/T is a perfect differential (=dS= dS) only for reversible processes; for irreversible processes, δQ<TdS\delta Q < T\,dS.

4. Thermodynamic Potentials

4.1 Motivation

The first law dU=δQδWdU = \delta Q - \delta W involves the path-dependent quantities QQ and WW. Thermodynamic potentials are state functions that replace QQ and WW with combinations of state variables, making analysis of equilibrium and spontaneity purely in terms of state variables.

4.2 The Four Potentials

PotentialSymbolNatural VariablesDifferential
Internal energyUUS,VS, VdU=TdSpdVdU = T\,dS - p\,dV
EnthalpyH=U+pVH = U + pVS,pS, pdH=TdS+VdpdH = T\,dS + V\,dp
Helmholtz free energyF=UTSF = U - TST,VT, VdF=SdTpdVdF = -S\,dT - p\,dV
Gibbs free energyG=HTSG = H - TST,pT, pdG=SdT+VdpdG = -S\,dT + V\,dp

Physical meaning:

  • HH: Total heat content at constant pressure; enthalpy change equals heat at constant pp.
  • FF: Maximum work extractable at constant TT. Equilibrium at constant T,VT, V: dF0dF \leq 0.
  • GG: Maximum non-expansion work at constant T,pT, p. Equilibrium at constant T,pT, p: dG0dG \leq 0.

4.3 Legendre Transforms

The potentials are related by Legendre transforms, which replace one natural variable with its conjugate:

H=U+pV(replace V by p),F=UTS(replace S by T),G=UTS+pVH = U + pV \quad (\text{replace } V \text{ by } p), \qquad F = U - TS \quad (\text{replace } S \text{ by } T), \qquad G = U - TS + pV

This structure is systematic: starting from the fundamental relation U(S,V)U(S, V), each Legendre transform swaps one variable for its conjugate to obtain a potential that is natural for different experimental conditions.

4.4 Equilibrium Conditions

At equilibrium, the relevant thermodynamic potential is minimised:

  • Constant S,VS, V: minimise UU (isolated system).
  • Constant S,pS, p: minimise HH (isobaric, adiabatic system).
  • Constant T,VT, V: minimise FF (isothermal, closed rigid system).
  • Constant T,pT, p: minimise GG (isothermal, isobaric system — most common).
Worked Example 4.1: Gibbs Free Energy of a Phase Transition

Consider melting of ice at T=273  KT = 273\;\text{K}, p=1  atmp = 1\;\text{atm}. At the melting point, both phases coexist in equilibrium, so ΔG=0\Delta G = 0.

ΔG=ΔHTΔS=0    ΔS=ΔHT=6010  J/mol273  K=22.0  J mol1K1\Delta G = \Delta H - T\Delta S = 0 \implies \Delta S = \frac{\Delta H}{T} = \frac{6010\;\text{J/mol}}{273\;\text{K}} = 22.0\;\text{J mol}^{-1}\text{K}^{-1}

Above 273  K273\;\text{K}, ΔG<0\Delta G < 0 for melting (spontaneous). Below 273  K273\;\text{K}, ΔG>0\Delta G > 0 (melting is non-spontaneous; freezing is).

5. Maxwell Relations

5.1 Derivation from Exact Differentials

Since UU, HH, FF, GG are state functions, their differentials are exact. For an exact differential dz=Mdx+Ndydz = M\,dx + N\,dy, the cross-partial derivatives are equal: M/y=N/x\partial M/\partial y = \partial N/\partial x.

Applying this to the four thermodynamic potentials:

From dU=TdSpdVdU = T\,dS - p\,dV:

(TV)S=(pS)V\left(\frac{\partial T}{\partial V}\right)_S = -\left(\frac{\partial p}{\partial S}\right)_V

From dH=TdS+VdpdH = T\,dS + V\,dp:

(Tp)S=(VS)p\left(\frac{\partial T}{\partial p}\right)_S = \left(\frac{\partial V}{\partial S}\right)_p

From dF=SdTpdVdF = -S\,dT - p\,dV:

(SV)T=(pT)V\left(\frac{\partial S}{\partial V}\right)_T = \left(\frac{\partial p}{\partial T}\right)_V

From dG=SdT+VdpdG = -S\,dT + V\,dp:

(Sp)T=(VT)p\left(\frac{\partial S}{\partial p}\right)_T = -\left(\frac{\partial V}{\partial T}\right)_p

These are the four Maxwell relations.

5.2 Applications

Example (Relation between CpC_p and CVC_V): Using Maxwell relations and the chain rule, this can be shown:

CpCV=T(pT)V(VT)pC_p - C_V = T\left(\frac{\partial p}{\partial T}\right)_V \left(\frac{\partial V}{\partial T}\right)_p

For an ideal gas, (pT)V=nR/V\left(\frac{\partial p}{\partial T}\right)_V = nR/V and (VT)p=nR/p\left(\frac{\partial V}{\partial T}\right)_p = nR/p, giving CpCV=nRC_p - C_V = nR.

Example (Internal energy of an ideal gas): Using the Maxwell relation (SV)T=(pT)V=nR/V\left(\frac{\partial S}{\partial V}\right)_T = \left(\frac{\partial p}{\partial T}\right)_V = nR/V and integrating:

(UV)T=T(pT)Vp=TnRVp=pp=0\left(\frac{\partial U}{\partial V}\right)_T = T\left(\frac{\partial p}{\partial T}\right)_V - p = T \cdot \frac{nR}{V} - p = p - p = 0

This proves that for an ideal gas, UU depends only on TT (Joule’s law).

6. Phase Transitions

6.1 Classification

Phase transitions are classified by the behaviour of thermodynamic quantities and their derivatives:

First-order transitions involve a discontinuity in a first derivative of the Gibbs free energy (e.g., VV or SS). There is latent heat:

ΔQ=TΔS=T(Sphase 2Sphase 1)\Delta Q = T \Delta S = T(S_{\text{phase 2}} - S_{\text{phase 1}})

Examples: melting, boiling, sublimation.

Second-order (continuous) transitions involve a discontinuity in a second derivative of GG (e.g., CpC_p, compressibility, thermal expansion coefficient). There is no latent heat.

Examples: superconducting transition, ferromagnetic Curie point, superfluid transition of 4^4He.

6.2 The Clausius–Clapeyron Equation

For a first-order phase transition along the coexistence curve:

dpdT=ΔSΔV=LTΔV\frac{dp}{dT} = \frac{\Delta S}{\Delta V} = \frac{L}{T \Delta V}

where L=TΔSL = T\Delta S is the latent heat and ΔV\Delta V is the volume change.

Application (liquid–vapour): If ΔVVgas=nRT/p\Delta V \approx V_{\text{gas}} = nRT/p (vapour treated as ideal gas, liquid volume neglected):

dpdT=LpnRT2    lnp=LnR1T+const\frac{dp}{dT} = \frac{Lp}{nRT^2} \implies \ln p = -\frac{L}{nR} \cdot \frac{1}{T} + \text{const}

This is the approximate form of the vapour pressure curve.

6.3 Critical Phenomena

At a critical point, the distinction between phases vanishes. For the liquid–vapour transition in a van der Waals gas, the critical point is at:

Tc=8a27bR,pc=a27b2,Vc=3nbT_c = \frac{8a}{27bR}, \qquad p_c = \frac{a}{27b^2}, \qquad V_c = 3nb

Near the critical point, thermodynamic quantities exhibit power-law behaviour characterised by critical exponents. For example, the order parameter (e.g., density difference between liquid and gas) vanishes as TTcβ|T - T_c|^\beta where β0.326\beta \approx 0.326 (the 3D Ising universality class).

6.4 Order Parameters

An order parameter is a thermodynamic quantity that is zero in one phase and nonzero in another:

  • Liquid–gas: density difference ρlρg\rho_l - \rho_g.
  • Ferromagnet: magnetisation MM.
  • Superconductor: energy gap Δ\Delta or superfluid density ρs\rho_s.

Landau theory provides a phenomenological framework: the free energy is expanded as a power series in the order parameter, with coefficients depending on temperature. Symmetry of the free energy determines which terms appear.

7. Statistical Mechanics Foundations

7.1 Microstates and Macrostates

A microstate is a complete specification of the state of a system (positions and momenta of all particles). A macrostate is specified by macroscopic variables (E,V,NE, V, N).

The fundamental postulate of statistical mechanics (postulate of equal a priori probabilities): an isolated system in equilibrium is equally likely to be found in any of its accessible microstates.

7.2 The Boltzmann Distribution

For a system in thermal equilibrium at temperature TT with a heat bath, the probability of the system being in microstate ii with energy EiE_i is:

pi=eβEiZp_i = \frac{e^{-\beta E_i}}{Z}

where β=1/(kBT)\beta = 1/(k_B T) and ZZ is the partition function.

7.3 The Partition Function

The canonical partition function for a system with discrete energy levels is:

Z=ieβEiZ = \sum_i e^{-\beta E_i}

For a classical ideal gas (continuous energies):

Z=1N!h3NeβH(p,q)d3Npd3NqZ = \frac{1}{N! h^{3N}} \int e^{-\beta H(\mathbf{p}, \mathbf{q})}\, d^{3N}p\, d^{3N}q

The partition function encodes all thermodynamic information:

U=lnZβ,F=kBTlnZ,S=kB(lnZ+βU)U = -\frac{\partial \ln Z}{\partial \beta}, \qquad F = -k_B T \ln Z, \qquad S = k_B(\ln Z + \beta U)

Worked Example 7.1: Partition Function of a Classical Ideal Gas

For NN non-interacting particles in a 3D box of volume VV:

Z1=Vλ3(single-particle partition function)Z_1 = \frac{V}{\lambda^3} \quad \text{(single-particle partition function)}

where λ=h/2πmkBT\lambda = h/\sqrt{2\pi m k_B T} is the thermal de Broglie wavelength.

ZN=Z1NN!=1N!(Vλ3)NZ_N = \frac{Z_1^N}{N!} = \frac{1}{N!}\left(\frac{V}{\lambda^3}\right)^N

F=kBTlnZN=kBT[NlnVλ3lnN!]F = -k_B T \ln Z_N = -k_B T \left[N \ln \frac{V}{\lambda^3} - \ln N!\right]

Using Stirling’s approximation lnN!NlnNN\ln N! \approx N \ln N - N:

F=NkBT[ln(Nλ3V)1]F = Nk_B T \left[\ln\left(\frac{N\lambda^3}{V}\right) - 1\right]

p=(FV)T=NkBTV(recovers ideal gas law)p = -\left(\frac{\partial F}{\partial V}\right)_T = \frac{Nk_B T}{V} \quad \text{(recovers ideal gas law)}

7.4 Connection to Thermodynamics

The statistical definition of entropy is:

S=kBlnΩS = k_B \ln \Omega

For the canonical ensemble:

S=kB(lnZ+βU)=(FT)VS = k_B(\ln Z + \beta U) = -\left(\frac{\partial F}{\partial T}\right)_V

This connects the microscopic counting of states to the macroscopic entropy defined by the Clausius relation dS=δQrev/TdS = \delta Q_{\text{rev}}/T.

8. Heat Engines and Refrigerators

8.1 Heat Engines

A heat engine converts heat into work by operating between a hot reservoir at THT_H and a cold reservoir at TCT_C.

Efficiency:

η=WQH=1QCQH\eta = \frac{W}{Q_H} = 1 - \frac{Q_C}{Q_H}

Carnot efficiency (maximum possible):

ηCarnot=1TCTH\eta_{\text{Carnot}} = 1 - \frac{T_C}{T_H}

8.2 Refrigerators and Heat Pumps

A refrigerator uses work to transfer heat from a cold reservoir to a hot reservoir.

Coefficient of Performance (refrigerator):

COPR=QCW=QCQHQC\text{COP}_R = \frac{Q_C}{W} = \frac{Q_C}{Q_H - Q_C}

Carnot COP (refrigerator):

COPR,Carnot=TCTHTC\text{COP}_{R,\text{Carnot}} = \frac{T_C}{T_H - T_C}

For a heat pump (heating mode):

COPHP=QHW=QHQHQC,COPHP,Carnot=THTHTC\text{COP}_{HP} = \frac{Q_H}{W} = \frac{Q_H}{Q_H - Q_C}, \qquad \text{COP}_{HP,\text{Carnot}} = \frac{T_H}{T_H - T_C}

8.3 The Otto Cycle

The Otto cycle models a petrol engine:

  1. Adiabatic compression (V1V2V_1 \to V_2).
  2. Isochoric combustion (V2=constV_2 = \text{const}, heat QHQ_H added).
  3. Adiabatic expansion / power stroke (V2V1V_2 \to V_1).
  4. Isochoric rejection (V1=constV_1 = \text{const}, heat QCQ_C expelled).

ηOtto=11rγ1\eta_{\text{Otto}} = 1 - \frac{1}{r^{\gamma-1}}

where r=V1/V2r = V_1/V_2 is the compression ratio. Higher rr gives higher efficiency, but in practice is limited by engine knock.

8.4 The Diesel Cycle

The Diesel cycle models a diesel engine:

  1. Adiabatic compression (V1V2V_1 \to V_2).
  2. Isobaric combustion (p=constp = \text{const}, heat QHQ_H added).
  3. Adiabatic expansion (V3V4V_3 \to V_4).
  4. Isochoric rejection (V4=constV_4 = \text{const}, heat QCQ_C expelled).

ηDiesel=11rγ1αγ1γ(α1)\eta_{\text{Diesel}} = 1 - \frac{1}{r^{\gamma-1}} \cdot \frac{\alpha^\gamma - 1}{\gamma(\alpha - 1)}

where r=V1/V2r = V_1/V_2 is the compression ratio and α=V3/V2\alpha = V_3/V_2 is the cut-off ratio.

Worked Example 8.1: Otto Cycle Efficiency

A petrol engine with compression ratio r=10r = 10 uses air (γ=1.4\gamma = 1.4):

η=11100.4=112.512=10.398=0.602\eta = 1 - \frac{1}{10^{0.4}} = 1 - \frac{1}{2.512} = 1 - 0.398 = 0.602

That is, 60.2% efficiency in the ideal Otto cycle. Real engines achieve roughly 25–35% due to friction, heat losses, incomplete combustion, and finite combustion speed.


9. Common Pitfalls

  1. “Heat and internal energy are the same thing.” Heat QQ is energy in transit due to a temperature difference; it is a path-dependent process quantity. Internal energy UU is a state function depending only on the current state. Adding heat does not “increase the heat” in a body — it increases the internal energy.

  2. ΔS=0\Delta S = 0 only for reversible processes.” False. Entropy is a state function, so ΔS\Delta S between two equilibrium states is the same regardless of path (reversible or irreversible). To calculate ΔS\Delta S, you imagine a reversible path between the same states, but the result is path-independent. What is path-dependent is the total entropy generation: ΔSgen=ΔSQ/Tsurr0\Delta S_{\text{gen}} = \Delta S - Q/T_{\text{surr}} \geq 0.

  3. “The Carnot efficiency applies to all heat engines.” The Carnot efficiency η=1TC/TH\eta = 1 - T_C/T_H is an upper bound achievable only by a reversible engine operating between two thermal reservoirs. Real engines (Otto, Diesel) operate between varying temperatures and are irreversible.

  4. “Free energy minimisation determines equilibrium in all conditions.” Different potentials are minimised under different constraints. At constant TT and pp, minimise GG. At constant TT and VV, minimise FF. At constant SS and VV, minimise UU. Applying the wrong potential leads to incorrect predictions.

  5. “The Maxwell relations are independent identities to be memorised.” All four follow from the exactness of the differential of one of the four thermodynamic potentials. They are systematically generated, not independent. If you remember the four differentials, you can derive all four relations on the spot using 2f/xy=2f/yx\partial^2 f/\partial x\partial y = \partial^2 f/\partial y\partial x.

  6. “At the critical point, the first-order phase transition becomes continuous.” The distinction between first-order and continuous is meaningful only away from the critical point. At the critical point itself, the transition is characterised by diverging correlation lengths and universal critical exponents, described by renormalisation group theory rather than classical thermodynamics alone.

  7. “The Boltzmann factor eβEe^{-\beta E} applies to isolated systems.” The Boltzmann distribution applies to a system in contact with a heat bath (canonical ensemble). For an isolated system with fixed total energy EE, the correct description is the microcanonical ensemble, where all accessible microstates at energy EE are equally probable.


10. Summary

  • Zeroth law establishes temperature as a transitive, well-defined equilibrium property.
  • First law (dU=δQδWdU = \delta Q - \delta W) is energy conservation; UU is a state function while QQ and WW are path-dependent.
  • Second law (ΔStotal0\Delta S_{\text{total}} \geq 0) dictates the direction of spontaneous processes and limits engine efficiency to η1TC/TH\eta \leq 1 - T_C/T_H.
  • Entropy (dS=δQrev/TdS = \delta Q_{\text{rev}}/T) measures irreversibility; Boltzmann’s formula S=kBlnΩS = k_B \ln \Omega connects it to microscopic state counting.
  • Thermodynamic potentials (UU, HH, FF, GG) replace path-dependent QQ and WW with state functions; each is natural for specific experimental conditions.
  • Maxwell relations follow from exact differentials and allow rewriting hard-to-measure partial derivatives in terms of accessible quantities.
  • Phase transitions are classified by discontinuities in derivatives of GG; the Clausius–Clapeyron equation governs coexistence curves; critical phenomena exhibit universal power laws.
  • Statistical mechanics provides the microscopic foundation via the partition function, which encodes all thermodynamic quantities through its logarithm and derivatives.
  • Heat engines (Carnot, Otto, Diesel) are limited by the second law; efficiency increases with compression ratio and temperature differential.

Cross-References

TopicLink
Classical MechanicsView
Quantum Mechanics IView
Solid State PhysicsView
ElectromagnetismView
MIT 5.60 ThermodynamicsView
Stanford Statistical MechanicsView

Worked Examples

Example 1: Carnot Efficiency Calculation

Problem: A Carnot engine operates between a hot reservoir at 600 K and a cold reservoir at 300 K. If the engine absorbs 1000 J of heat per cycle, how much work is done and how much heat is rejected? Solution: Efficiency eta = 1 - T_c/T_h = 1 - 300/600 = 0.50 (50%). Work = eta _ Q_h = 0.50 _ 1000 = 500 J. Q_c = Q_h - W = 1000 - 500 = 500 J. The engine rejects 500 J of heat to the cold reservoir per cycle.

Example 2: Entropy Change of Phase Transition

Problem: Calculate the entropy change when 1 mol of ice melts at 0 degrees C. Delta H_fusion = 6.01 kJ/mol. Solution: Delta S = q_rev/T = Delta H_fusion / T = 6010 J / 273.15 K = 22.0 J K^-1 mol^-1. The entropy increases because the solid (ordered) becomes liquid (more disordered).

Cross-References

TopicLink
Quantum Mechanics IIView
Kinetic TheoryView