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Problem Set

Problem 1. Using the Gell-Mann—Nishijima formula, determine the electric charge of the Σ\Sigma^* baryon with quark content ssssss.

Problem 2. A particle XX decays via the strong interaction: Xp+K+X \to p + K^+. Determine The quark content, baryon number, strangeness, and charge of XX. Classify XX as a meson or Baryon.

Problem 3. Show that the decay Λ0n+π0\Lambda^0 \to n + \pi^0 is allowed, while Λ0p+π\Lambda^0 \to p + \pi^- is forbidden by strangeness conservation. Through which Interaction does the Λ0\Lambda^0 actually decay?

Problem 4. Compute the branching ratio upper bound for π0e+e\pi^0 \to e^+e^- relative to π0γγ\pi^0 \to \gamma\gamma using dimensional analysis and helicity suppression.

Problem 5. In the decay μe+νˉe+νμ\mu^- \to e^- + \bar{\nu}_e + \nu_\muVerify that Electric charge, baryon number, and all three lepton family numbers are conserved.

Problem 6. Draw the Feynman diagram for e+ee+ee^+e^- \to e^+e^- (Bhabha scattering) at tree Level. Identify both the ss-channel and tt-channel diagrams.

Problem 7. For Compton scattering eγeγe^-\gamma \to e^-\gamma in the low-energy limit, Derive the Thomson cross section σT=8πα2/(3me2)\sigma_T = 8\pi\alpha^2/(3m_e^2) from the Klein—Nishina Formula.

Problem 8. Calculate the QED running coupling α\alpha at the ZZ boson mass scale (mZ=91.2m_Z = 91.2 GeV), given α(me)1/137\alpha(m_e) \approx 1/137.

Problem 9. For the Higgs potential V=μ2ϕϕ+λ(ϕϕ)2V = \mu^2\phi^\dagger\phi + \lambda(\phi^\dagger\phi)^2 With μ2<0\mu^2 \lt 0Show that expanding the field around the VEV ϕ=(0,v)T/2\phi = (0, v)^T/\sqrt{2} Produces a physical scalar with mass mH=2λvm_H = \sqrt{2\lambda}\,v. Identify the three Goldstone Modes.

Problem 10. The top quark has mass mt=173m_t = 173 GeV/c2c^2 and the electron has mass me=0.511m_e = 0.511 MeV/c2c^2. Compute the ratio of their Yukawa couplings. What does this imply About the origin of the fermion mass hierarchy?

Problem 11. Verify that the SU(3) structure constant f123=1f^{123} = 1 by explicitly computing [λ1,λ2][\lambda^1, \lambda^2] and showing it equals 2iλ32i\lambda^3.

Problem 12. Use the Gell-Mann—Okubo mass formula for the baryon octet, 12(mN+mΞ)=14(3mΛ+mΣ)\frac{1}{2}(m_N + m_\Xi) = \frac{1}{4}(3m_\Lambda + m_\Sigma)And the experimental masses mp=938.3m_p = 938.3 MeV, mn=939.6m_n = 939.6 MeV, mΞ0=1314.9m_{\Xi^0} = 1314.9 MeV, mΞ=1321.7m_{\Xi^-} = 1321.7 MeV, mΛ=1115.7m_\Lambda = 1115.7 MeV, mΣ+=1189.4m_{\Sigma^+} = 1189.4 MeV, mΣ0=1192.6m_{\Sigma^0} = 1192.6 MeV, mΣ=1197.4m_{\Sigma^-} = 1197.4 MeV. Compute both sides and find the percentage discrepancy.

Problem 13. Compute the QCD beta function coefficient b0=112nf/3b_0 = 11 - 2n_f/3 for nf=4n_f = 4, 55And 66 active flavours. At what number of flavours does asymptotic freedom Break down?

Problem 14. For a flat, matter-dominated universe with H0=70H_0 = 70 km/s/Mpc, compute: (a) the critical density ρc\rho_c in kg/m3^3(b) the age of the universe t0=2/(3H0)t_0 = 2/(3H_0) And (c) the Hubble distance dH=c/H0d_H = c/H_0.

Problem 15. A supernova at redshift z=0.5z = 0.5 is observed to be fainter than predicted By the matter-dominated Friedmann model. Using the deceleration parameter q0q_0Show that q0<0q_0 \lt 0 is required and that this implies ΩΛ>Ωm/2\Omega_\Lambda \gt \Omega_m/2.

Problem 16. Solar neutrinos are produced by p+pd+e++νep + p \to d + e^+ + \nu_e with energy Eν0.42E_\nu \leq 0.42 MeV. Using the two-flavour oscillation formula with Δm212=7.5×105\Delta m^2_{21} = 7.5 \times 10^{-5} eV2^2 and sin2(2θ12)=0.84\sin^2(2\theta_{12}) = 0.84Calculate The oscillation probability P(νeνμ)P(\nu_e \to \nu_\mu) at the distance L=1.5×1011L = 1.5 \times 10^{11} m (Earth—Sun distance). Take Eν=0.3E_\nu = 0.3 MeV. (Express LL and EE in natural units.)

Problem 17. In the seesaw mechanism, if the Dirac mass is mD=mtop=173m_D = m_{\mathrm{top} = 173} GeV And the heavy Majorana mass is M=1014M = 10^{14} GeV, calculate the resulting light neutrino mass. Compare this with the cosmological bound mν<0.12\sum m_\nu \lt 0.12 eV.

Problem 18. The Ω\Omega^- baryon (ssssss) was predicted by Gell-Mann in 1962 using the Decuplet equal-spacing rule. Given the masses mΔ=1232m_\Delta = 1232 MeV, mΣ=1385m_{\Sigma^*} = 1385 MeV, And mΞ=1533m_{\Xi^*} = 1533 MeV, predict mΩm_{\Omega^-}. Compare with the measured value of 1672.51672.5 MeV and comment on the agreement.

Problem 19. (Dark matter) The rotational velocity of stars in the Milky Way is observed to be approximately constant at v220v \approx 220 km/s out to at least r=20r = 20 kpc. Assuming a spherical dark matter halo with density profile ρ(r)=ρ0/(1+(r/rs)2)\rho(r) = \rho_0 / (1 + (r/r_s)^2), compute the enclosed mass M(r)M(r) and show that v(r)v(r) is approximately flat for rrsr \gg r_s.

Problem 20. (Neutrino oscillations) A neutrino produced as νμ\nu_\mu with energy E=1E = 1 GeV travels L=1000L = 1000 km. Given Δm322=2.5×103\Delta m_{32}^2 = 2.5 \times 10^{-3} eV2^2 and sin2(2θ23)=1.0\sin^2(2\theta_{23}) = 1.0, calculate the oscillation probability P(νμντ)P(\nu_\mu \to \nu_\tau). Express LL and EE in natural units (=c=1\hbar = c = 1).

Problem 21. (Cosmic microwave background) The CMB temperature today is T0=2.725T_0 = 2.725 K. (a) Compute the energy density of the CMB photon gas. (b) At what redshift zz did the CMB temperature equal T=3000T = 3000 K (recombination epoch)? (c) Estimate the baryon-to-photon ratio η\eta given that the baryon density today is Ωbh2=0.022\Omega_b h^2 = 0.022.

Problem 22. (Running coupling unification) Plot (conceptually) the running of the three gauge couplings α1\alpha_1, α2\alpha_2, α3\alpha_3 in the Standard Model as a function of energy scale. Explain why minimal SU(5) unification fails: the couplings do not meet at a single point. How does supersymmetry (MSSM) resolve this?

Selected Solutions

Problem 9. The Higgs potential minimum occurs at ϕϕ=μ2/(2λ)=v2/2\phi^\dagger\phi = -\mu^2/(2\lambda) = v^2/2. Writing ϕ=(0,v+h)T/2\phi = (0, v + h)^T/\sqrt{2} and substituting gives the Higgs mass mH=2λvm_H = \sqrt{2\lambda}\,v. The three Goldstone modes correspond to the three broken generators of SU(2)L_L, which become the longitudinal components of W±W^\pm and ZZ.

Problem 10. The Yukawa coupling is yf=2mf/vy_f = \sqrt{2}\,m_f/v where v=246v = 246 GeV. yt/ye=mt/me=173 GeV/0.511 MeV3.4×105y_t/y_e = m_t/m_e = 173\ \mathrm{GeV} / 0.511\ \mathrm{MeV} \approx 3.4 \times 10^5. This large hierarchy suggests that the fermion masses arise from a more fundamental mechanism.

Problem 14. ρc=3H02/(8πG)1.88×1026h2 kg/m3\rho_c = 3H_0^2/(8\pi G) \approx 1.88 \times 10^{-26}\,h^2\ \mathrm{kg/m}^3 with h=H0/(100 km/s/Mpc)=0.7h = H_0/(100\ \mathrm{km/s/Mpc}) = 0.7, giving ρc9.2×1027 kg/m3\rho_c \approx 9.2 \times 10^{-27}\ \mathrm{kg/m}^3. t0=2/(3H0)9.3×109t_0 = 2/(3H_0) \approx 9.3 \times 10^9 years (for a matter-dominated flat universe). dH=c/H04280 Mpcd_H = c/H_0 \approx 4280\ \mathrm{Mpc}.

Problem 16. In natural units =c=1\hbar = c = 1: L=1.5×1011 m7.6×1020 GeV1L = 1.5 \times 10^{11}\ \mathrm{m} \approx 7.6 \times 10^{20}\ \mathrm{GeV}^{-1}, E=0.3E = 0.3 MeV. The oscillation phase is Δm2L/(4E)1.24\Delta m^2 L/(4E) \approx 1.24, giving P(νeνμ)=sin2(2θ12)sin2(Δm2L/(4E))0.84×0.950.80P(\nu_e \to \nu_\mu) = \sin^2(2\theta_{12}) \sin^2(\Delta m^2 L/(4E)) \approx 0.84 \times 0.95 \approx 0.80.

Problem 17. mν=mD2/M(173 GeV)2/1014 GeV0.3m_\nu = m_D^2/M \approx (173\ \mathrm{GeV})^2 / 10^{14}\ \mathrm{GeV} \approx 0.3 eV. This is above the cosmological bound mν<0.12\sum m_\nu < 0.12 eV, suggesting either a smaller Dirac mass or a larger Majorana mass.

Problem 18. The decuplet equal-spacing rule predicts mΩ=mΞ+(mΞmΣ)=1533+(15331385)=1681m_{\Omega^-} = m_{\Xi^*} + (m_{\Xi^*} - m_{\Sigma^*}) = 1533 + (1533 - 1385) = 1681 MeV. The measured value is 1672.51672.5 MeV, a discrepancy of 0.5%0.5\%, which was a spectacular confirmation of SU(3) flavour symmetry and led to the discovery of the Ω\Omega^- at Brookhaven in 1964.

Problem 19. For ρ(r)=ρ0/(1+(r/rs)2)\rho(r) = \rho_0/(1 + (r/r_s)^2), the enclosed mass is M(r)=4π0rρ(r)r2dr=4πρ0rs3[r/rsarctan(r/rs)]M(r) = 4\pi\int_0^r \rho(r') r'^2\,dr' = 4\pi\rho_0 r_s^3[r/r_s - \arctan(r/r_s)]. The circular velocity is v2(r)=GM(r)/rv^2(r) = GM(r)/r. For rrsr \gg r_s, M(r)rM(r) \propto r, giving v4πGρ0rs2v \approx \sqrt{4\pi G\rho_0 r_s^2}, which is constant — explaining the flat rotation curves.

Problem 22. The gauge couplings run according to the renormalisation group equations: μdαi1/dμ=bi/(2π)\mu d\alpha_i^{-1}/d\mu = -b_i/(2\pi). In the SM, b=(41/10,19/6,7)b = (41/10, -19/6, -7) for U(1), SU(2), SU(3) respectively. The couplings nearly meet at MU1015M_U \sim 10^{15} GeV but do not intersect at a single point. In the MSSM, the beta coefficients change to (33/5,1,3)(33/5, 1, -3), and the couplings unify at MU2×1016M_U \sim 2\times 10^{16} GeV, providing indirect evidence for supersymmetry.