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Transport Properties

8.1 Electrical Conductivity: Drude Model

The Drude model treats conduction electrons as a classical gas scattering off ions with a mean Free time τ\tau.

Under an electric field E\mathbf{E}The equation of motion:

medvdt=eEmevτm_e\frac{d\mathbf{v}}{dt} = -e\mathbf{E} - \frac{m_e\mathbf{v}}{\tau}

In steady state (dv/dt=0d\mathbf{v}/dt = 0): vd=eτmeE\mathbf{v}_d = -\frac{e\tau}{m_e}\mathbf{E}.

The current density: J=nevd=ne2τmeE\mathbf{J} = -ne\mathbf{v}_d = \frac{ne^2\tau}{m_e}\mathbf{E}.

The Drude conductivity:

σ=ne2τme\sigma = \frac{ne^2\tau}{m_e}

The mean free path: =vFτ\ell = v_F\tau.

Successes: Explains Ohm”s law (J=σE\mathbf{J} = \sigma\mathbf{E}) and the Wiedemann—Franz law (κ/σ=LT\kappa/\sigma = LT with L=π2kB2/(3e2)L = \pi^2 k_B^2/(3e^2)).

Failures: Predicts the wrong temperature dependence (ρT\rho \propto TBut experiments show ρT5\rho \propto T^5 at low TT for pure metals). Predicts γelectron=32nkB\gamma_{\mathrm{electron} = \frac{3}{2}nk_B} But experiments give γelectron=π22nkB(T/TF)\gamma_{\mathrm{electron} = \frac{\pi^2}{2}nk_B(T/T_F)} (much smaller).

8.2 The Boltzmann Transport Equation

The semiclassical distribution function f(r,k,t)f(\mathbf{r}, \mathbf{k}, t) satisfies:

ft+vkrfeEkf=(ft)coll\frac{\partial f}{\partial t} + \mathbf{v}_{\mathbf{k}} \cdot \nabla_{\mathbf{r}} f - \frac{e\mathbf{E}}{\hbar}\cdot\nabla_{\mathbf{k}} f = \left(\frac{\partial f}{\partial t}\right)_{\mathrm{coll}}

In the relaxation time approximation:

(ft)coll=ff0τ\left(\frac{\partial f}{\partial t}\right)_{\mathrm{coll} = -\frac{f - f_0}{\tau}}

Where f0f_0 is the equilibrium distribution.

Solution for conductivity. In a uniform electric field with f=f0+f1f = f_0 + f_1:

f1=eτEvkf0εf_1 = e\tau\mathbf{E}\cdot\mathbf{v}_{\mathbf{k}}\frac{\partial f_0}{\partial\varepsilon}

The conductivity becomes:

σ=e23τ(ε)v2(ε)g(ε)(f0ε)dε\sigma = \frac{e^2}{3}\int \tau(\varepsilon)\,v^2(\varepsilon)\,g(\varepsilon)\left(-\frac{\partial f_0}{\partial\varepsilon}\right) d\varepsilon

At low TT, f0/εδ(εεF)-\partial f_0/\partial\varepsilon \approx \delta(\varepsilon - \varepsilon_F)So only states Near EFE_F contribute to transport. This explains why impurity scattering dominates at low TT (even a small concentration of impurities affects states near EFE_F).

Matthiessen’s rule. When multiple scattering mechanisms act independently, the total resistivity Is approximately additive:

ρ(T)=ρ0+ρph(T)\rho(T) = \rho_0 + \rho_{\mathrm{ph}(T)}

Where ρ0\rho_0 is the residual resistivity (temperature-independent, from impurities and defects) And ρph(T)\rho_{\mathrm{ph}(T)} is the phonon contribution (proportional to TT at high TT and to T5T^5 At low TT via the Bloch—Grüneisen formula). The resistance ratio RRR=ρ(300 K)/ρ0RRR = \rho(300\ \mathrm{K})/\rho_0 Is a measure of sample purity.

Bloch—Grüneisen formula. For electron—phonon scattering in a free electron metal:

ρph(T)(TΘD)50ΘD/Tx5(ex1)(1ex)dx\rho_{\mathrm{ph}(T) \propto \left(\frac{T}{\Theta_D}\right)^5 \int_0^{\Theta_D/T} \frac{x^5}{(e^x - 1)(1 - e^{-x})}\,dx}

At high TT (T>ΘDT \gt \Theta_D): ρphT\rho_{\mathrm{ph} \propto T} (linear, agreeing with the Drude model). At low TT (TΘDT \ll \Theta_D): ρphT5\rho_{\mathrm{ph} \propto T^5}Consistent with experiment.

8.3 Thermal Conductivity

The thermal conductivity of electrons:

κe=13cevFe\kappa_e = \frac{1}{3}c_e v_F \ell_e

Where ce=π22nkB(T/TF)c_e = \frac{\pi^2}{2}nk_B(T/T_F) is the electronic specific heat. The phonon contribution:

κph=13CVvsph\kappa_{\mathrm{ph} = \frac{1}{3}C_V v_s \ell_{\mathrm{ph}}}

The total thermal conductivity: κ=κe+κph\kappa = \kappa_e + \kappa_{\mathrm{ph}}.

8.4 The Hall Effect

When a magnetic field B=Bz^\mathbf{B} = B\hat{\mathbf{z}} is applied perpendicular to a current J=Jxx^\mathbf{J} = J_x\hat{\mathbf{x}}A transverse electric field develops:

Ey=RHJxBE_y = R_H J_x B

The Hall coefficient: RH=1/(ne)R_H = -1/(ne) for a single carrier type.

The Hall angle: θH=arctan(Ey/Ex)=ωcτ\theta_H = \arctan(E_y/E_x) = \omega_c\tau where ωc=eB/m\omega_c = eB/m^* is the Cyclotron frequency.

8.5 Effective Mass

Near a band extremum, the energy can be expanded:

ε(k)=ε0+22ij(m1)ijkikj\varepsilon(\mathbf{k}) = \varepsilon_0 + \frac{\hbar^2}{2}\sum_{ij}(m^{-1})_{ij}k_i k_j

The effective mass tensor (m1)ij=122εkikj(m^{-1})_{ij} = \frac{1}{\hbar^2}\frac{\partial^2 \varepsilon}{\partial k_i \partial k_j} Determines the response to external fields. For isotropic bands, m=2/(d2ε/dk2)m^* = \hbar^2/(d^2\varepsilon/dk^2).

A large effective mass means a flat band (small group velocity). A small effective mass means a Steep band (high mobility).