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Approximation Methods

8.1 Time-Independent Perturbation Theory

For a Hamiltonian H^=H^0+λH^"\hat{H} = \hat{H}_0 + \lambda \hat{H}" where H^\hat{H}' is “small” and H^0\hat{H}_0 Has known eigenstates n(0)|n^{(0)}\rangle and eigenvalues En(0)E_n^{(0)}.

First-order energy correction:

En(1)=n(0)H^n(0)E_n^{(1)} = \langle n^{(0)} | \hat{H}' | n^{(0)} \rangle

Second-order energy correction:

En(2)=mnm(0)H^n(0)2En(0)Em(0)E_n^{(2)} = \sum_{m \neq n} \frac{|\langle m^{(0)} | \hat{H}' | n^{(0)} \rangle|^2}{E_n^{(0)} - E_m^{(0)}}

First-order state correction:

n(1)=mnm(0)H^n(0)En(0)Em(0)m(0)|n^{(1)}\rangle = \sum_{m \neq n} \frac{\langle m^{(0)} | \hat{H}' | n^{(0)} \rangle}{E_n^{(0)} - E_m^{(0)}} |m^{(0)}\rangle

Physical interpretation. The first-order energy correction is the expectation value of the Perturbation in the unperturbed state. The second-order correction accounts for virtual transitions To other states: if the perturbation mixes in state m|m\rangle with amplitude proportional to Vmn/(EnEm)V_{mn}/(E_n - E_m)The energy shift is the sum of Vmn2/(EnEm)|V_{mn}|^2/(E_n - E_m) over all Intermediate states. Lower-energy intermediate states (Em<EnE_m \lt E_n) always lower the energy, While higher-energy ones raise it.

Higher-order corrections. The perturbation series can be extended to arbitrary order:

En=En(0)+λEn(1)+λ2En(2)+λ3En(3)+E_n = E_n^{(0)} + \lambda E_n^{(1)} + \lambda^2 E_n^{(2)} + \lambda^3 E_n^{(3)} + \cdots

n=n(0)+λn(1)+λ2n(2)+|n\rangle = |n^{(0)}\rangle + \lambda|n^{(1)}\rangle + \lambda^2|n^{(2)}\rangle + \cdots

The series converges if λmH^nEn(0)Em(0)\lambda|\langle m|\hat{H}'|n\rangle| \ll |E_n^{(0)} - E_m^{(0)}| for all mnm \neq n. In practice, low-order corrections often give excellent results for weak perturbations.

8.2 Degenerate Perturbation Theory

When En(0)E_n^{(0)} is degenerate, the corrections are found by diagonalising the perturbation matrix in The degenerate subspace.

Theorem 8.1. The correct zeroth-order states are the eigenvectors of the matrix Wij=ni(0)H^nj(0)W_{ij} = \langle n_i^{(0)} | \hat{H}' | n_j^{(0)} \rangle within the degenerate subspace.

Proof. In a dd-dimensional degenerate subspace spanned by n1(0),,nd(0)\\{|n_1^{(0)}\rangle, \ldots, |n_d^{(0)}\rangle\\} The first-order correction to the states is undetermined by the non-degenerate formula (denominators Vanish). The correct approach is to note that H^\hat{H} restricted to this subspace is:

H^sub=En(0)I^+λW^\hat{H}_{\mathrm{sub} = E_n^{(0)}\hat{I} + \lambda \hat{W}}

Where Wij=ni(0)H^nj(0)W_{ij} = \langle n_i^{(0)}|\hat{H}'|n_j^{(0)}\rangle. Diagonalising W^\hat{W} gives the correct Zeroth-order states and first-order energy splittings. \blacksquare

8.3 Worked Example: Perturbed Infinite Square Well

Problem. A one-dimensional infinite square well of width LL has a small perturbation H=V0H' = V_0 for 0<x<L/20 \lt x \lt L/2 and H=0H' = 0 for L/2<x<LL/2 \lt x \lt L. Find the first-order energy Corrections.

Solution

The unperturbed states are ϕn(0)(x)=2/Lsin(nπx/L)\phi_n^{(0)}(x) = \sqrt{2/L}\sin(n\pi x/L).

En(1)=n(0)Hn(0)=0L/2V02Lsin2 ⁣(nπxL)dxE_n^{(1)} = \langle n^{(0)} | H' | n^{(0)} \rangle = \int_0^{L/2} V_0 \frac{2}{L}\sin^2\!\left(\frac{n\pi x}{L}\right) dx

=2V0L0L/21cos(2nπx/L)2dx=V0L ⁣[L2L4nπsin(nπ)]=V02= \frac{2V_0}{L}\int_0^{L/2} \frac{1 - \cos(2n\pi x/L)}{2}\, dx = \frac{V_0}{L}\!\left[\frac{L}{2} - \frac{L}{4n\pi}\sin(n\pi)\right] = \frac{V_0}{2}

The first-order correction is En(1)=V0/2E_n^{(1)} = V_0/2 for all nn. \blacksquare

:::caution Common Pitfall Perturbation theory assumes the perturbation is “small” compared to the level spacing. If mHnEn(0)Em(0)|\langle m | H' | n \rangle| \sim |E_n^{(0)} - E_m^{(0)}|The perturbation series may diverge. The Method also fails for systems where the unperturbed Hamiltonian has closely spaced or degenerate Levels that are not handled correctly.

8.4 Variational Principle

Theorem 8.2 (Variational Principle). For any normalised trial state ϕ|\phi\rangle:

ϕH^ϕE0\langle\phi|\hat{H}|\phi\rangle \geq E_0

Where E0E_0 is the true ground state energy. The equality holds if and only if ϕ=0|\phi\rangle = |0\rangle.

Proof. Expand the trial state in the energy eigenbasis:

ϕ=n=0cnn,ncn2=1|\phi\rangle = \sum_{n=0}^{\infty} c_n |n\rangle, \quad \sum_n |c_n|^2 = 1

Then:

ϕH^ϕ=ncn2EnE0ncn2=E0\langle\phi|\hat{H}|\phi\rangle = \sum_n |c_n|^2 E_n \geq E_0\sum_n |c_n|^2 = E_0

Since EnE0E_n \geq E_0 for all nnAnd the inequality is strict unless cn=0c_n = 0 for all n1n \geq 1. \blacksquare

Procedure. Choose a trial wave function ϕ(x;α1,α2,)\phi(x; \alpha_1, \alpha_2, \ldots) depending on variational Parameters αi\alpha_i. Compute E(αi)=ϕH^ϕ/ϕϕE(\alpha_i) = \langle\phi|\hat{H}|\phi\rangle / \langle\phi|\phi\rangle And minimise with respect to αi\alpha_i. The minimum provides an upper bound on E0E_0.

Example 8.1. Use a Gaussian trial function ϕ(x)=Aexp(x2/(2α2))\phi(x) = A\exp(-x^2/(2\alpha^2)) to estimate the Ground state energy of the anharmonic oscillator V(x)=12mω2x2+λx4V(x) = \frac{1}{2}m\omega^2 x^2 + \lambda x^4.

Solution

The normalised Gaussian is ϕ(x)=(πα2)1/4exp(x2/(2α2))\phi(x) = (\pi\alpha^2)^{-1/4}\exp(-x^2/(2\alpha^2)) with x2=α2/2\langle x^2 \rangle = \alpha^2/2 and x4=3α4/4\langle x^4 \rangle = 3\alpha^4/4.

T=p22m=24mα2\langle T \rangle = \frac{\langle p^2 \rangle}{2m} = \frac{\hbar^2}{4m\alpha^2}

(by using p=id/dxp = -i\hbar\,d/dx and integrating by parts).

V=12mω2x2+λx4=mω2α24+3λα44\langle V \rangle = \frac{1}{2}m\omega^2\langle x^2 \rangle + \lambda\langle x^4 \rangle = \frac{m\omega^2\alpha^2}{4} + \frac{3\lambda\alpha^4}{4}

E(α)=24mα2+mω2α24+3λα44E(\alpha) = \frac{\hbar^2}{4m\alpha^2} + \frac{m\omega^2\alpha^2}{4} + \frac{3\lambda\alpha^4}{4}

Minimising: dE/dα=0dE/d\alpha = 0 gives 2/(2mα3)+mω2α/2+3λα3=0-\hbar^2/(2m\alpha^3) + m\omega^2\alpha/2 + 3\lambda\alpha^3 = 0.

For λ=0\lambda = 0 (harmonic oscillator), this gives α2=/(mω)\alpha^2 = \hbar/(m\omega) and E=ω/2E = \hbar\omega/2Which is exact. For small λ\lambdaExpand α2=/(mω)(1δ)\alpha^2 = \hbar/(m\omega)(1 - \delta):

α2mω ⁣(13λ2m2ω3)\alpha^2 \approx \frac{\hbar}{m\omega}\!\left(1 - \frac{3\lambda\hbar}{2m^2\omega^3}\right)

Evarω2 ⁣(1+3λ4m2ω3)E_{\mathrm{var} \approx \frac{\hbar\omega}{2}\!\left(1 + \frac{3\lambda\hbar}{4m^2\omega^3}\right)}

This agrees with second-order perturbation theory to first order in λ\lambda.

8.5 WKB Approximation

The WKB (Wentzel-Kramers-Brillouin) method provides approximate solutions to the one-dimensional Schrodinger equation when the potential varies slowly compared to the de Broglie wavelength.

Ansatz. Write ψ(x)=A(x)exp(iS(x)/)\psi(x) = A(x)\exp(iS(x)/\hbar) and substitute into the Schrodinger equation:

iAS2AS+2AS2AS2=(terms)-i\hbar A'S - \hbar^2 A S'' + \hbar^2 A S'^2 - A S' \cdot \hbar^2 = \mathrm{(terms)}

Actually, substituting directly into 2ψ/(2m)+Vψ=Eψ-\hbar^2\psi''/(2m) + V\psi = E\psi and separating orders of \hbar:

Leading order (0\hbar^0): S(x)=±p(x)=±2m(EV(x))S'(x) = \pm p(x) = \pm\sqrt{2m(E - V(x))}

Next order (1\hbar^1): A(x)/A(x)=S(x)/(2S(x))A'(x)/A(x) = -S''(x)/(2S'(x))Giving A(x)1/p(x)A(x) \propto 1/\sqrt{p(x)}.

Therefore, in the classically allowed region (E>VE \gt V):

ψ(x)Cp(x)cos ⁣(1x1xp(x)dx+π4)\psi(x) \approx \frac{C}{\sqrt{p(x)}}\cos\!\left(\frac{1}{\hbar}\int_{x_1}^x p(x')\,dx' + \frac{\pi}{4}\right)

Where x1x_1 is a turning point (E=V(x1)E = V(x_1)).

Connection formulas. At a turning point, the WKB solutions must be matched. The standard Connection formula (for a linear turning point, V(x)E+V(x1)(xx1)V(x) \approx E + V'(x_1)(x-x_1)) gives:

  • Approaching from the classically allowed side: 2Cp(x)cos ⁣(1x1xp(x)dxπ4)Cp(x)exp ⁣(1xx1p(x)dx)\frac{2C}{\sqrt{p(x)}}\cos\!\left(\frac{1}{\hbar}\int_{x_1}^x p(x')\,dx' - \frac{\pi}{4}\right) \longleftrightarrow \frac{C}{\sqrt{|p(x)|}}\exp\!\left(-\frac{1}{\hbar}\int_x^{x_1} |p(x')|\,dx'\right)

Quantization condition. For a potential well with turning points x1x_1 and x2x_2Applying the Connection formulas at both ends yields:

x1x2p(x)dx=(n+12)π,n=0,1,2,\int_{x_1}^{x_2} p(x)\,dx = \left(n + \frac{1}{2}\right)\pi\hbar, \quad n = 0, 1, 2, \ldots

Equivalently, using the closed phase-space integral:

pdx=(n+12)h\oint p\,dx = \left(n + \frac{1}{2}\right)h

This is the Bohr-Sommerfeld quantization condition, corrected by the 1/21/2 term from the connection Formulas.

Validity. The WKB approximation requires dλ/dx1|d\lambda/dx| \ll 1Where λ=h/p(x)\lambda = h/p(x) is the Local de Broglie wavelength. Equivalently, the change in potential over one wavelength must be small Compared to the kinetic energy: V(x)/(2mp(x))1|\hbar\,|V'(x)|/(2mp(x))| \ll 1.

Example 8.2. Apply the WKB quantization condition to the harmonic oscillator.

Solution

For V(x)=12mω2x2V(x) = \frac{1}{2}m\omega^2 x^2The turning points are at x1,2=±2E/(mω2)x_{1,2} = \pm\sqrt{2E/(m\omega^2)}.

x1x22m ⁣(E12mω2x2)dx=2mEaa1(x/a)2dx\int_{x_1}^{x_2} \sqrt{2m\!\left(E - \frac{1}{2}m\omega^2 x^2\right)}\,dx = \sqrt{2mE}\int_{-a}^{a}\sqrt{1 - (x/a)^2}\,dx

Where a=2E/(mω2)a = \sqrt{2E/(m\omega^2)}. The integral equals πa/2\pi a/2 times 2mE\sqrt{2mE}:

=2mEπa2=πEω= \sqrt{2mE}\cdot\frac{\pi a}{2} = \frac{\pi E}{\omega}

Setting this equal to (n+1/2)π(n + 1/2)\pi\hbar:

πEω=(n+12)π    En=(n+12)ω\frac{\pi E}{\omega} = \left(n + \frac{1}{2}\right)\pi\hbar \implies E_n = \left(n + \frac{1}{2}\right)\hbar\omega

This is the exact result! The WKB approximation gives the exact energy levels for the harmonic Oscillator because the potential is quadratic, so the connection formulas are exact.

Validity and limitations. The WKB method fails near turning points (where E=V(x)E = V(x)) because p(x)0p(x) \to 0 and the local wavelength diverges. The linear approximation of the potential near Turning points (used to derive the connection formulas) breaks down when the potential is not smooth. The method also fails for potentials with discontinuities or cusps.

Despite these limitations, WKB is remarkably useful for estimating energy levels in potentials Where exact solutions are not available, and it forms the basis of the JWKB approximation in Scattering theory.

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