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Variational Methods

10.1 The Variational Principle

For any trial wavefunction ψtrial\psi_{\text{trial}} (normalised), the expectation value of the Hamiltonian is an upper bound on the true ground state energy:

Etrial=ψtrialH^ψtrialE0E_{\text{trial} = \langle\psi_{\text{trial}|\hat{H}|\psi_{\text{trial}\rangle \geq E_0}}}

The equality holds if and only if ψtrial=ψ0\psi_{\text{trial} = \psi_0}.

10.2 The Hydrogen Molecule Ion H2+H_2^+

The simplest molecule: one electron in the field of two protons separated by distance RR. The Hamiltonian:

H^=22me2e24πε0rAe24πε0rB+e24πε0R\hat{H} = -\frac{\hbar^2}{2m_e}\nabla^2 - \frac{e^2}{4\pi\varepsilon_0 r_A} - \frac{e^2}{4\pi\varepsilon_0 r_B} + \frac{e^2}{4\pi\varepsilon_0 R}

LCAO trial function: ψ±=N±[ψ1s(rA)±ψ1s(rB)]\psi_\pm = N_\pm[\psi_{1s}(\mathbf{r}_A) \pm \psi_{1s}(\mathbf{r}_B)]

The energies:

E±(R)=E1s+e24πε0R+J±K1±SE_\pm(R) = E_{1s} + \frac{e^2}{4\pi\varepsilon_0 R} + \frac{J \pm K}{1 \pm S}

Where S=ψAψBS = \langle\psi_A|\psi_B\rangle is the overlap integral, JJ is the Coulomb integral, and KK is the exchange integral.

  • EE_- (bonding): has a minimum at R2.5a0R \approx 2.5\,a_0Giving a binding energy of 1.8\sim 1.8 eV (experiment: 2.8 eV).
  • E+E_+ (antibonding): monotonically decreases, no bound state.

10.3 The Hydrogen Molecule H2H_2

With two electrons, the full Hamiltonian includes the electron-electron repulsion. Using the variational method with properly (anti)symmetrised spatial-spin wavefunctions:

Bonding (singlet): Esinglet=2E1s+e2R+2J+2K1+S2E_{\text{singlet} = 2E_{1s} + \frac{e^2}{R} + \frac{2J + 2K}{1 + S^2}}

Antibonding (triplet): Etriplet=2E1s+e2R+2J2K1S2E_{\text{triplet} = 2E_{1s} + \frac{e^2}{R} + \frac{2J - 2K}{1 - S^2}}

The equilibrium bond length is Re1.4a0R_e \approx 1.4\,a_0 with binding energy 3.5\sim 3.5 eV (experiment: 4.75 eV).

Worked Example 10.1: Variational Estimate for Helium Ground State

Use the trial function ψtrial=(Zeff3/πa03)exp(Zeffr1/a0)exp(Zeffr2/a0)\psi_{\text{trial} = (Z_{\text{eff}^3/\pi a_0^3)\exp(-Z_{\text{eff}r_1/a_0)\exp(-Z_{\text{eff}r_2/a_0)}}}} where ZeffZ_{\text{eff}} is a variational parameter.

The energy expectation value (treating the electron-electron repulsion as a perturbation):

E(Z_{\text{eff}) = 2\times\frac{Z_{\text{eff}^2}{2}\text{Ry} - 2\times\frac{Z_{\text{eff} Z}{1}\text{Ry} + \frac{5}{8}Z_{\text{eff}\text{Ry}}}}}

= \left(Z_{\text{eff}^2 - 4Z_{\text{eff} + \frac{5}{4}Z_{\text{eff}\right)\text{Ry} = \left(Z_{\text{eff}^2 - \frac{11}{4}Z_{\text{eff}\right)\text{Ry}}}}}}

Minimising: E/Zeff=(2Zeff11/4)=0    Zeff=11/8=1.375\partial E/\partial Z_{\text{eff} = (2Z_{\text{eff} - 11/4) = 0 \implies Z_{\text{eff} = 11/8 = 1.375}}}.

E=(1216412132)Ry=12164Ry=2.848Ry=77.5 eVE = \left(\frac{121}{64} - \frac{121}{32}\right)\text{Ry} = -\frac{121}{64}\text{Ry} = -2.848\text{Ry} = -77.5\ \text{eV}

The exact (non-relativistic) ground state energy is 79.0-79.0 eV, so the variational result is within 2%.

The effective charge Zeff=1.375<2Z_{\text{eff} = 1.375 < 2} reflects the screening of the nuclear charge by the other electron: each electron partially shields the nucleus from the other, reducing the effective charge from Z=2Z = 2 to Zeff1.375Z_{\text{eff} \approx 1.375}.