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Coherence

Coherence time τc\tau_c: the time over which the wave maintains a well-defined phase.

Coherence length: Lc=cτcL_c = c\tau_c.

For a source with spectral width Δν\Delta\nu:

τc1Δν,LccΔν=λ2Δλ\tau_c \approx \frac{1}{\Delta\nu}, \quad L_c \approx \frac{c}{\Delta\nu} = \frac{\lambda^2}{\Delta\lambda}

A sodium lamp (Δλ0.6\Delta\lambda \approx 0.6 nm at λ=589\lambda = 589 nm) has Lc0.6L_c \approx 0.6 mm. A laser (Δλ106\Delta\lambda \approx 10^{-6} nm) has Lc300L_c \approx 300 m.

Worked Example: Coherence length and fringe visibility

Problem. A mercury lamp emits light at λ=546.1\lambda = 546.1 nm with a spectral width Δλ=0.025\Delta\lambda = 0.025 nm. (a) Find the coherence length. (b) In a Michelson interferometer, at what Path difference does the fringe visibility drop to 1/e1/e? (c) How many fringes are visible before they Wash out?

Solution.

(a) Lc=λ2/Δλ=(546.1×109)2/(0.025×109)=1.19×102L_c = \lambda^2/\Delta\lambda = (546.1 \times 10^{-9})^2/(0.025 \times 10^{-9}) = 1.19 \times 10^{-2} m =11.9= 11.9 mm.

(b) For a Gaussian spectrum, visibility drops to 1/e1/e when Δx=Lc=11.9\Delta x = L_c = 11.9 mm.

(c) The number of fringes: Nfringes=Lc/λ=(11.9×103)/(546.1×109)=2.18×104N_{\mathrm{fringes} = L_c/\lambda = (11.9 \times 10^{-3})/(546.1 \times 10^{-9}) = 2.18 \times 10^4}. Over 20000 fringes are visible — a large number, but far fewer than for a laser.

The van Cittert-Zernike theorem states that the spatial coherence of light from an extended Incoherent source is given by the Fourier transform of the source intensity distribution.

For a circular source of angular diameter θs\theta_sThe transverse coherence length is:

lc1.22λθsl_c \approx \frac{1.22\lambda}{\theta_s}

The mutual coherence function quantifies the correlation between the wave field at two spacetime points:

Γ12(τ)=E(r1,t)E(r2,t+τ)\Gamma_{12}(\tau) = \langle E^*(r_1, t) E(r_2, t + \tau) \rangle

The complex degree of coherence is the normalised quantity:

γ12(τ)=Γ12(τ)Γ11(0)Γ22(0)\gamma_{12}(\tau) = \frac{\Gamma_{12}(\tau)}{\sqrt{\Gamma_{11}(0) \Gamma_{22}(0)}}

For quasi-monochromatic light, the visibility of interference fringes equals γ12(τ)|\gamma_{12}(\tau)|. Fringes are visible when 0<γ10 < |\gamma| \leq 1, with γ=1|\gamma| = 1 for perfectly coherent light and γ=0|\gamma| = 0 for incoherent light.

8.4 First-Order Coherence and the Wiener-Khinchin Theorem

Section titled “8.4 First-Order Coherence and the Wiener-Khinchin Theorem”

The Wiener-Khinchin theorem relates the power spectral density S(ω)S(\omega) of a stationary random process to the autocorrelation function via Fourier transform:

Γ11(τ)=S(ω)eiωτdω\Gamma_{11}(\tau) = \int_{-\infty}^{\infty} S(\omega) e^{-i\omega\tau} d\omega

The coherence time is inversely related to the spectral width: τc=γ11(τ)2dτ\tau_c = \int_{-\infty}^{\infty} |\gamma_{11}(\tau)|^2 d\tau. For a Lorentzian line shape, τc=1/(πΔν)\tau_c = 1/(\pi\Delta\nu).

8.5 Partial Coherence and the Wolf Equations

Section titled “8.5 Partial Coherence and the Wolf Equations”

Partially coherent light is described by the cross-spectral density function W(r1,r2,ω)W(r_1, r_2, \omega), which is the Fourier transform of the mutual coherence function:

W(r1,r2,ω)=12πΓ(r1,r2,τ)eiωτdτW(r_1, r_2, \omega) = \frac{1}{2\pi} \int_{-\infty}^{\infty} \Gamma(r_1, r_2, \tau) e^{i\omega\tau} d\tau

The Wolf equations govern the propagation of the cross-spectral density, generalising the Helmholtz equation to partially coherent fields.

8.6 Second-Order Coherence and Photon Bunching

Section titled “8.6 Second-Order Coherence and Photon Bunching”

Second-order coherence measures intensity correlations:

g(2)(τ)=I(t)I(t+τ)I(t)2g^{(2)}(\tau) = \frac{\langle I(t) I(t+\tau) \rangle}{\langle I(t) \rangle^2}

  • Thermal light (chaotic): g(2)(0)=2g^{(2)}(0) = 2, exhibiting photon bunching.
  • Coherent light (laser): g(2)(τ)=1g^{(2)}(\tau) = 1 for all τ\tau.
  • Antibunched light (single-photon source): g(2)(0)<1g^{(2)}(0) < 1.

The Hanbury Brown-Twiss (HBT) interferometer measures g(2)(τ)g^{(2)}(\tau) and was originally used to measure the angular diameter of stars. The HBT effect demonstrated that intensity correlations contain information about source size even when first-order coherence is absent.

8.7 Worked Example: Fringe Visibility of Two Spectral Lines

Section titled “8.7 Worked Example: Fringe Visibility of Two Spectral Lines”

Problem. A source emits two equal-intensity spectral lines at λ1\lambda_1 and λ2\lambda_2 with Δλ=λ2λ1λ\Delta\lambda = |\lambda_2 - \lambda_1| \ll \lambda. Find the fringe visibility in a Michelson interferometer as a function of path difference.

Solution

The interference pattern is the sum of patterns from each line:

I=I0[2+cos ⁣(2πΔxλ1)+cos ⁣(2πΔxλ2)]I = I_0\left[2 + \cos\!\left(\frac{2\pi\Delta x}{\lambda_1}\right) + \cos\!\left(\frac{2\pi\Delta x}{\lambda_2}\right)\right]

Using the sum-to-product identity:

I=2I0[1+cos ⁣(πΔxλ1+πΔxλ2)cos ⁣(πΔxλ1πΔxλ2)]I = 2I_0\left[1 + \cos\!\left(\frac{\pi\Delta x}{\lambda_1} + \frac{\pi\Delta x}{\lambda_2}\right) \cos\!\left(\frac{\pi\Delta x}{\lambda_1} - \frac{\pi\Delta x}{\lambda_2}\right)\right]

For Δλλ\Delta\lambda \ll \lambda, this becomes:

I=2I0[1+cos ⁣(2πΔxλˉ)cos ⁣(πΔxΔλλˉ2)]I = 2I_0\left[1 + \cos\!\left(\frac{2\pi\Delta x}{\bar{\lambda}}\right) \cos\!\left(\frac{\pi\Delta x\,\Delta\lambda}{\bar{\lambda}^2}\right)\right]

where λˉ\bar{\lambda} is the mean wavelength. The fringe visibility is cos(πΔxΔλ/λˉ2)|\cos(\pi\Delta x\,\Delta\lambda/\bar{\lambda}^2)|, which drops to zero when Δx=λˉ2/(2Δλ)\Delta x = \bar{\lambda}^2/(2\Delta\lambda). This is the coherence length for a two-line source.

\blacksquare

8.8 Worked Example: Michelson Stellar Interferometer

Section titled “8.8 Worked Example: Michelson Stellar Interferometer”

Two separated mirrors direct light from a distant star into a single telescope. Fringes are observed When the mirror separation dd satisfies:

d<1.22λθsd \lt \frac{1.22\lambda}{\theta_s}

The first disappearance of fringes gives the angular diameter of the star: θs=1.22λ/d\theta_s = 1.22\lambda/d.

8.9 Coherence of Laser Light vs Thermal Light

Section titled “8.9 Coherence of Laser Light vs Thermal Light”
PropertyLaserThermal source
Spectral width Δν\Delta\nu1\sim 1 MHz or less1014\sim 10^{14} Hz
Coherence time τc\tau_c1 μ\sim 1\ \mus or more1014\sim 10^{-14} s
Coherence length LcL_c300\sim 300 m or more1 μ\sim 1\ \mum
Spatial coherenceFull (across beam)Limited by van Cittert-Zernike
g(2)(0)g^{(2)}(0)11 (coherent)22 (chaotic)

8.10 Worked Example: Spatial Coherence of Sunlight

Section titled “8.10 Worked Example: Spatial Coherence of Sunlight”

Problem. The sun has an angular diameter of approximately 0.530.53^\circ as seen from Earth. What is the transverse coherence length of sunlight at λ=550\lambda = 550 nm?

Solution

The angular diameter in radians: θs=0.53×π/1809.25×103\theta_s = 0.53^\circ \times \pi/180 \approx 9.25 \times 10^{-3} rad.

Using the van Cittert-Zernike theorem for a circular source:

lc1.22λθs=1.22×550×1099.25×1037.3×105 m73 μml_c \approx \frac{1.22\lambda}{\theta_s} = \frac{1.22 \times 550 \times 10^{-9}}{9.25 \times 10^{-3}} \approx 7.3 \times 10^{-5}\ \text{m} \approx 73\ \mu\text{m}

This means sunlight is coherent over a distance of about 73 μ73\ \mum transverse to the propagation direction. Two pinholes spaced closer than this will produce visible interference fringes.

\blacksquare