Geometric Optics
6.1 Reflection and Refraction
Law of Reflection: The angle of incidence equals the angle of reflection: (both measured from the normal).
Snell”s Law: .
Derivation of Snell’s law from Fermat’s principle. The optical path length from point in Medium 1 to point in medium 2 via a point on the interface at is:
Setting :
Which gives .
6.2 Total Internal Reflection
When light travels from a denser to a rarer medium (), total internal reflection occurs When where:
Evanescent wave. Beyond the critical angle, the transmitted field decays exponentially:
Where .
6.3 The Thin Lens Equation
Where is the object distance, is the image distance, and is the focal length.
Sign convention (Cartesian): Distances are positive in the direction of light propagation. For converging lenses, for diverging.
Magnification:
Negative indicates an inverted image.
6.4 Lensmaker’s Equation
For a thin lens with radii of curvature and :
6.5 Matrix Optics (Ray Transfer Matrix)
A paraxial ray is described by a vector where is the Height and is the angle with the optical axis.
Free space propagation by distance :
Thin lens of focal length :
System matrix: The overall transformation is the product of individual matrices (applied in Reverse order): .
6.6 Mirror Equation
For a spherical mirror of radius (with for concave, for convex):
The focal length is . The magnification is (negative for inverted images).
Derivation from the law of reflection. A ray from the object at height striking the mirror At height reflects such that . In the paraxial approximation (), Applying the law of reflection and the small-angle approximation :
Dividing through by and using , (paraxial rays) yields the mirror Equation.
Worked Example: Concave mirror image formation
Problem. A concave mirror has radius of curvature cm. An object of height 2.0 cm is Placed 25 cm from the mirror. Find the image position, magnification, and nature.
Solution. cm. Using : So cm.
The image is real (positive ) and on the same side as the object.
.
Image height: cm (inverted, magnified by 4).
6.7 Optical Instruments
Magnifying glass. Angular magnification when the image is at the near point :
Compound microscope. Total magnification:
Where is the tube length, is the objective focal length, and is the eyepiece focal Length.
Refracting telescope. Angular magnification:
For large magnification, the objective should have a long focal length and the eyepiece a short one. The length of the telescope tube is approximately .
Reflecting telescope. A concave primary mirror replaces the objective lens. The Cassegrain design Uses a secondary convex mirror to redirect the focus behind the primary. Advantages: no chromatic Aberration, lighter and cheaper for large apertures, and easier support structures.
Worked Example: Compound microscope magnification
Problem. A compound microscope has an objective with mm and an eyepiece with mm. The tube length is mm. Find the total magnification when the final image Is at the near point ( mm).
Solution. Objective magnification: .
Eyepiece magnification (image at near point): .
Total magnification: .
The negative sign indicates the image is inverted.