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The Debye Model of Solids

16.1 From Einstein to Debye

The Einstein model treats all atoms as independent quantum oscillators with the same frequency ωE\omega_E:

CV=3NkB(θET)2eθE/T(eθE/T1)2C_V = 3Nk_B\left(\frac{\theta_E}{T}\right)^2 \frac{e^{\theta_E/T}}{(e^{\theta_E/T} - 1)^2}

Where θE=ωE/kB\theta_E = \hbar\omega_E/k_B. This correctly predicts CV0C_V \to 0 as T0T \to 0But gives CVeθE/TC_V \propto e^{-\theta_E/T} at low TTWhereas experiments show CVT3C_V \propto T^3.

The Debye model treats the lattice vibrations as a continuum of phonon modes with a cutoff frequency ωD\omega_D:

g(ω)=3Vω22π2vs3for0ωωDg(\omega) = \frac{3V\omega^2}{2\pi^2 v_s^3} \quad \text{for} 0 \leq \omega \leq \omega_D

Where vsv_s is the average sound speed. The cutoff is determined by the total number of modes:

0ωDg(ω)dω=3N    ωD=vs(6π2N/V)1/3\int_0^{\omega_D} g(\omega)\,d\omega = 3N \implies \omega_D = v_s(6\pi^2 N/V)^{1/3}

16.2 Debye Specific Heat

The internal energy:

E=0ωDωeβω1g(ω)dω=3V2π2vs30ωDω3eβω1dωE = \int_0^{\omega_D} \frac{\hbar\omega}{e^{\beta\hbar\omega} - 1}\, g(\omega)\, d\omega = \frac{3V\hbar}{2\pi^2 v_s^3}\int_0^{\omega_D} \frac{\omega^3}{e^{\beta\hbar\omega} - 1}\, d\omega

With x=ω/kBTx = \hbar\omega/k_BT and θD=ωD/kB\theta_D = \hbar\omega_D/k_B (Debye temperature):

E=9NkBT(TθD)30θD/Tx3ex1dxE = 9Nk_BT\left(\frac{T}{\theta_D}\right)^3 \int_0^{\theta_D/T} \frac{x^3}{e^x - 1}\, dx

The specific heat:

CV=9NkB(TθD)30θD/Tx4ex(ex1)2dxC_V = 9Nk_B\left(\frac{T}{\theta_D}\right)^3 \int_0^{\theta_D/T} \frac{x^4 e^x}{(e^x - 1)^2}\, dx

Low-temperature limit (TθDT \ll \theta_D):

CV=12π45NkB(TθD)3T3C_V = \frac{12\pi^4}{5}Nk_B\left(\frac{T}{\theta_D}\right)^3 \propto T^3

High-temperature limit (TθDT \gg \theta_D): CV3NkBC_V \to 3Nk_B (Dulong—Petit).

Worked Example 16.1: Debye Temperature of Aluminum

Aluminum has M=27M = 27 g/mol, ρ=2.70\rho = 2.70 g/cm3^3, vs6420v_s \approx 6420 m/s.

n=ρNAM=2.70×103×6.022×102327×103=6.02×1028 m3n = \frac{\rho N_A}{M} = \frac{2.70 \times 10^3 \times 6.022 \times 10^{23}}{27 \times 10^{-3}} = 6.02 \times 10^{28} \text{ m}^{-3}

ωD=vs(6π2n)1/3=6420×(6π2×6.02×1028)1/3\omega_D = v_s(6\pi^2 n)^{1/3} = 6420 \times (6\pi^2 \times 6.02 \times 10^{28})^{1/3}

=6420×(3.56×1030)1/3=6420×1.526×1010=9.80×1013 rad/s= 6420 \times (3.56 \times 10^{30})^{1/3} = 6420 \times 1.526 \times 10^{10} = 9.80 \times 10^{13} \text{ rad/s}

θD=ωDkB=1.055×1034×9.80×10131.38×1023748 K\theta_D = \frac{\hbar\omega_D}{k_B} = \frac{1.055 \times 10^{-34} \times 9.80 \times 10^{13}}{1.38 \times 10^{-23}} \approx 748 \text{ K}

The experimental value is θD428\theta_D \approx 428 K. The discrepancy arises from the oversimplified single sound-speed approximation.