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Rigid Body Dynamics: Advanced Topics

For a rigid body rotating freely (no external torques), the angular momentum in the body frame satisfies:

I1ω˙1(I2I3)ω2ω3=0I_1\dot{\omega}_1 - (I_2 - I_3)\omega_2\omega_3 = 0

I2ω˙2(I3I1)ω3ω1=0I_2\dot{\omega}_2 - (I_3 - I_1)\omega_3\omega_1 = 0

I3ω˙3(I1I2)ω1ω2=0I_3\dot{\omega}_3 - (I_1 - I_2)\omega_1\omega_2 = 0

Where I1,I2,I3I_1, I_2, I_3 are the principal moments of inertia and ω1,ω2,ω3\omega_1, \omega_2, \omega_3 are the angular velocity components in the body frame.

First integral: The kinetic energy T=12(I1ω12+I2ω22+I3ω32)T = \frac{1}{2}(I_1\omega_1^2 + I_2\omega_2^2 + I_3\omega_3^2) and the angular momentum magnitude L2=I12ω12+I22ω22+I32ω32L^2 = I_1^2\omega_1^2 + I_2^2\omega_2^2 + I_3^2\omega_3^2 are both conserved.

Geometric interpretation. The trajectory on the angular velocity ellipsoid I1ω12+I2ω22+I3ω32=2TI_1\omega_1^2 + I_2\omega_2^2 + I_3\omega_3^2 = 2T intersects the angular momentum sphere I12ω12+I22ω22+I32ω32=L2I_1^2\omega_1^2 + I_2^2\omega_2^2 + I_3^2\omega_3^2 = L^2 to give the polhode curve.

For an axisymmetric body (I1=I2I3I_1 = I_2 \neq I_3):

  • Rotation about the symmetry axis (ω3\omega_3): The body is stable if I3I_3 is either the largest or smallest moment. This explains why a spinning top is stable but rotation about the intermediate axis is not.

  • Tennis racket theorem (Dzhanibekov effect): Rotation about the intermediate axis (I1<I2<I3I_1 < I_2 < I_3, spinning about the I2I_2 axis) is unstable. Small perturbations cause the body to flip periodically.

Proof of instability for intermediate axis. Linearise Euler’s equations about ω=(0,Ω,0)\boldsymbol{\omega} = (0, \Omega, 0):

I1ω˙1=(I2I3)Ωω3I_1\dot{\omega}_1 = (I_2 - I_3)\Omega\,\omega_3

I3ω˙3=(I1I2)Ωω1I_3\dot{\omega}_3 = (I_1 - I_2)\Omega\,\omega_1

Combining: ω¨1=(I2I3)(I1I2)I1I3Ω2ω1\ddot{\omega}_1 = \frac{(I_2 - I_3)(I_1 - I_2)}{I_1 I_3}\Omega^2\,\omega_1. Since I1<I2<I3I_1 < I_2 < I_3, both factors in the numerator are negative, giving a positive coefficient: ω1\omega_1 grows exponentially. The motion is unstable. \blacksquare

Physical examples:

  1. Book toss: Throw a book spinning about each of its three axes. Rotation about the shortest and longest axes is stable; rotation about the intermediate axis causes flipping.
  2. Satellite attitude: Gravity-gradient stabilisation exploits the fact that rotation about the axis of minimum moment of inertia is stable in a gravitational field.

9.3 The Symmetric Top with One Point Fixed

Section titled “9.3 The Symmetric Top with One Point Fixed”

A symmetric top (I1=I2I_1 = I_2) with one point fixed, under gravity, is described by three Euler angles (ϕ,θ,ψ)(\phi, \theta, \psi).

The Lagrangian:

L=12I1(θ˙2+ϕ˙2sin2θ)+12I3(ψ˙+ϕ˙cosθ)2MgdcosθL = \frac{1}{2}I_1(\dot{\theta}^2 + \dot{\phi}^2\sin^2\theta) + \frac{1}{2}I_3(\dot{\psi} + \dot{\phi}\cos\theta)^2 - Mgd\cos\theta

Conserved quantities: pϕp_\phi (angular momentum about the vertical) and pψp_\psi (angular momentum about the symmetry axis) are cyclic:

pϕ=I1ϕ˙sin2θ+I3(ψ˙+ϕ˙cosθ)cosθ=constp_\phi = I_1\dot{\phi}\sin^2\theta + I_3(\dot{\psi} + \dot{\phi}\cos\theta)\cos\theta = \text{const}

pψ=I3(ψ˙+ϕ˙cosθ)=constp_\psi = I_3(\dot{\psi} + \dot{\phi}\cos\theta) = \text{const}

Steady precession. For θ˙=0\dot{\theta} = 0 (constant inclination θ0\theta_0):

ϕ˙=MgdI3ω3(regular precession)\dot{\phi} = \frac{Mgd}{I_3\omega_3} \quad \text{(regular precession)}

Nutation. When θ\theta varies, the tip of the symmetry axis traces a nutation path. The effective potential:

Veff(θ)=(pϕpψcosθ)22I1sin2θ+MgdcosθV_{\text{eff}}(\theta) = \frac{(p_\phi - p_\psi\cos\theta)^2}{2I_1\sin^2\theta} + Mgd\cos\theta

has a minimum at θ0\theta_0 for stable regular precession. Oscillation about θ0\theta_0 gives nutation with frequency:

ωnut=I3ω3I1(for rapid spin)\omega_{\text{nut}} = \frac{I_3\omega_3}{I_1} \quad \text{(for rapid spin)}

A spinning wheel with angular momentum L\mathbf{L} subject to a torque τ\boldsymbol{\tau} precesses:

Ωprec=τ×LL2\boldsymbol{\Omega}_{\text{prec}} = \frac{\boldsymbol{\tau} \times \mathbf{L}}{L^2}

Why the wheel doesn’t fall. Gravity produces a torque perpendicular to L\mathbf{L}, causing L\mathbf{L} to rotate horizontally rather than the wheel falling. The precession rate is:

Ωprec=MgdI3ω3\Omega_{\text{prec}} = \frac{Mgd}{I_3\omega_3}

Gyroscopic inertia. A rapidly spinning top resists tilting because changing the direction of L\mathbf{L} requires a torque proportional to ω3\omega_3.

When two rigid bodies are connected (e.g., a gyroscope on a gimbal), the system has additional degrees of freedom. The equations of motion couple through constraint forces at the joint.

Gimbal lock. In a three-gimbal system, when two gimbal axes align, one degree of freedom is lost. This is a kinematic singularity, not a dynamic one. Quaternion-based representations avoid gimbal lock entirely.

  1. Using lab-frame equations in the body frame. Euler’s equations apply in the body frame where the inertia tensor is diagonal. In the lab frame, the inertia tensor is time-dependent.

  2. Confusing ω3\omega_3 (body frame) with ϕ˙\dot{\phi} (lab frame). The angular velocity about the symmetry axis in the body frame includes contributions from both ψ˙\dot{\psi} and ϕ˙\dot{\phi}.

  3. Ignoring the stability criterion. Free rotation about the intermediate axis is always unstable. Assuming stability without checking the moment ordering leads to incorrect predictions.

  4. Neglecting nutation in fast-spinning tops. For ω3Ωprec\omega_3 \gg \Omega_{\text{prec}}, nutation is rapid and small-amplitude, but it is always present unless the initial conditions are precisely tuned to regular precession.

  5. Assuming I1=I2I_1 = I_2 (symmetric top) applies generally. The symmetric-top simplification ϕ˙=I3ω3/(I1ω1)\dot{\phi} = I_3\omega_3/(I_1\omega_1) only holds when the two transverse moments of inertia are equal. For an asymmetric top (I1I2I_1 \neq I_2), the motion is far more complex and may exhibit chaotic tumbling.

  6. Confusing precession with rotation. Precession is the slow rotation of the angular momentum vector L\mathbf{L} about the vertical; the top itself spins rapidly about its symmetry axis. These are distinct motions with very different timescales.

The effective potential for the θ\theta motion:

Veff(θ)=(pϕpψcosθ)22I1sin2θ+pψ22I3+MgdcosθV_{\text{eff}(\theta) = \frac{(p_\phi - p_\psi\cos\theta)^2}{2I_1\sin^2\theta} + \frac{p_\psi^2}{2I_3} + Mgd\cos\theta}

Nutation: The top nutates (oscillates in θ\theta) while precessing in ϕ\phi and spinning in ψ\psi. The type of nutation (looping, cusped, or smooth) depends on the initial conditions.

Fast top (pψMgdp_\psi \gg Mgd): The precession rate is:

ϕ˙Mgdpψ=MgdI3ω3\dot{\phi} \approx \frac{Mgd}{p_\psi} = \frac{Mgd}{I_3\omega_3}

This is independent of θ\theta to leading order (steady precession).

Worked Example 9.1: Precession of a Gyroscope

A gyroscope has I3=5×104I_3 = 5 \times 10^{-4} kg\cdotM2^2Mass M=0.5M = 0.5 kg, distance from pivot to centre of mass d=0.05d = 0.05 m, and spins at ω3=300\omega_3 = 300 rad/s.

The precession rate:

ϕ˙=MgdI3ω3=0.5×9.81×0.055×104×300=0.2450.15=1.63 rad/s15.6 rpm\dot{\phi} = \frac{Mgd}{I_3\omega_3} = \frac{0.5 \times 9.81 \times 0.05}{5 \times 10^{-4} \times 300} = \frac{0.245}{0.15} = 1.63\ \text{rad}/s \approx 15.6\ \text{rpm}

The precession period: T=2π/ϕ˙=3.85T = 2\pi/\dot{\phi} = 3.85 s.

If the spin is reduced to ω3=30\omega_3 = 30 rad/s (10 times slower), the precession rate increases by a factor of 10 to 16.3 rad/s. At some critical spin rate, the gyroscope can no longer maintain steady precession and topples.

  • Inertial navigation. Gyroscopes maintain a fixed orientation in space, providing angular rate measurements for aircraft and spacecraft. Ring laser gyroscopes measure rotation via the Sagnac effect with accuracy 0.001°\sim 0.001°/hr.
  • Satellite attitude control. Reaction wheels (spinning flywheels) exchange angular momentum with the spacecraft body to reorient without thrusters.
  • Balance in animals. The inner ear contains fluid-filled semicircular canals that act as biological gyroscopes, detecting head rotation for balance. Damage to these canals causes vertigo and loss of spatial orientation.
  • Tennis racket theorem (Dzhanibekov effect). A rigid body rotating about its intermediate axis spontaneously flips 180° periodically, visible in microgravity. This confirms the instability of intermediate-axis rotation predicted by Euler’s equations.
QuantityExpressionNotes
Euler’s equationsI1ω˙1=(I2I3)ω2ω3I_1\dot{\omega}_1 = (I_2 - I_3)\omega_2\omega_3Body frame, no external torque
Tilted top precessionϕ˙=I3ω3/(I1ω1)\dot{\phi} = I_3\omega_3/(I_1\omega_1)Angle between L\mathbf{L} and symmetry axis
Fast-top precessionϕ˙Mgd/(I3ω3)\dot{\phi} \approx Mgd/(I_3\omega_3)Independent of θ\theta to leading order
Nutation frequencyθ˙\dot{\theta} oscillates in VeffV_{\text{eff}}Looping/cusped/smooth types

These relationships apply to free rigid bodies (no external torque) and tops (constant gravity). For coupled or driven systems, numerical integration of the full Euler equations is typically required.