Skip to content

Summary of Key Results

| Theorem | Conditions | Conclusion | | ---------------------- | ----------------------------------------- | ---------------------------------------- | --------------- | ------------------------ | | Monotone Convergence | 0fnf0 \leq f_n \nearrow f | limfn=f\lim \int f_n = \int f | | Fatou”s Lemma | fn0f_n \geq 0 | lim inffnlim inffn\int \liminf f_n \leq \liminf \int f_n | | Dominated Convergence | fnff_n \to f, fngL1| f_n | \leq g \in L^1 | limfn=f\lim \int f_n = \int f | | Holder’s Inequality | fLpf \in L^p, gLqg \in L^q, 1/p+1/q=11/p + 1/q = 1 | fg1fpgq\|fg\|_1 \leq \|f\|_p \|g\|_q | | Minkowski’s Inequality | f,gLpf, g \in L^p | f+gpfp+gp\|f + g\|_p \leq \|f\|_p + \|g\|_p | | Fubini | fL1(μ×ν)f \in L^1(\mu \times \nu) | Iterated integrals equal double integral | | Radon-Nikodym | νμ\nu \ll \mu, σ\sigma-finite | dν/dμd\nu/d\mu exists and is unique a.e. |

Statement. If {fn}\{f_n\} is a sequence of measurable functions such that 0f1f20 \leq f_1 \leq f_2 \leq \cdots and fnff_n \to f pointwise, then fdμ=limnfndμ\int f\,d\mu = \lim_{n\to\infty} \int f_n\,d\mu.

Intuition. The monotone convergence theorem (MCT) allows the interchange of limit and integral when the functions are non-negative and increase monotonically. It is the primary tool for proving convergence of integrals when the integrands are positive.

Application. To compute 0xp1exdx=Γ(p)\int_0^\infty x^{p-1} e^{-x}\,dx = \Gamma(p), one expresses the integrand as the increasing limit of functions xp1ex1[0,n](x)x^{p-1} e^{-x} \mathbf{1}_{[0,n]}(x) and applies MCT.

Statement. If {fn}\{f_n\} is a sequence of non-negative measurable functions, then lim infnfndμlim infnfndμ\int \liminf_{n\to\infty} f_n\,d\mu \leq \liminf_{n\to\infty} \int f_n\,d\mu.

Intuition. Fatou’s lemma gives a one-sided inequality that holds without any convergence assumptions. It is often used as a stepping stone to prove the dominated convergence theorem.

Common Pitfall. The inequality can be strict. For example, fn=1[n,n+1]f_n = \mathbf{1}_{[n,n+1]} on R\mathbb{R} with Lebesgue measure: lim inffn=0\liminf f_n = 0 so the left side is 00, but fn=1\int f_n = 1 for each nn, so the right limit inferior is 11.

Statement. Suppose fnff_n \to f pointwise a.e. and fng|f_n| \leq g for all nn where gL1g \in L^1. Then fnf\int f_n \to \int f.

Intuition. The dominated convergence theorem (DCT) is the workhorse of measure theory. It allows interchange of limit and integral provided the functions are dominated by an integrable function. The dominating function must be in L1L^1, not merely bounded.

Application. Continuity of the Laplace transform: for F(t)=0etxf(x)dxF(t) = \int_0^\infty e^{-tx} f(x)\,dx, if fL1f \in L^1, then FF is continuous on [0,)[0,\infty) by DCT.

Statement. For measurable functions ff and gg, if fLpf \in L^p and gLqg \in L^q where 1/p+1/q=11/p + 1/q = 1, then fgL1fg \in L^1 and fgfpgq\int |fg| \leq \|f\|_p \|g\|_q.

Intuition. H”older’s inequality generalises the Cauchy-Schwarz inequality (the special case p=q=2p = q = 2). It is fundamental for establishing duality between LpL^p and LqL^q spaces.

Proof Sketch. By Young’s inequality abap/p+bq/qab \leq a^p/p + b^q/q for a,b0a, b \geq 0. Apply this to a=f/fpa = |f|/\|f\|_p, b=g/gqb = |g|/\|g\|_q and integrate.

Statement. For f,gLpf, g \in L^p with 1p1 \leq p \leq \infty, we have f+gpfp+gp\|f + g\|_p \leq \|f\|_p + \|g\|_p.

Intuition. Minkowski’s inequality is the triangle inequality for the LpL^p norm. It establishes that LpL^p is a normed vector space. For p<1p < 1, the reverse inequality holds.

Proof Sketch. Write f+gpf+gp1f+f+gp1g|f+g|^p \leq |f+g|^{p-1}|f| + |f+g|^{p-1}|g|, apply H”older with exponents pp and p/(p1)p/(p-1), then divide.

Statement. Let fL1(μ×ν)f \in L^1(\mu \times \nu) on a product measure space. Then: X×Yfd(μ×ν)=X(Yf(x,y)dν(y))dμ(x)=Y(Xf(x,y)dμ(x))dν(y)\int_{X \times Y} f\,d(\mu \times \nu) = \int_X \left(\int_Y f(x,y)\,d\nu(y)\right) d\mu(x) = \int_Y \left(\int_X f(x,y)\,d\mu(x)\right) d\nu(y).

Intuition. Fubini’s theorem justifies interchanging the order of integration. The key condition is absolute integrability with respect to the product measure.

Common Pitfall. Without L1L^1 condition, the iterated integrals may differ. The classic counterexample is f(x,y)=(x2y2)/(x2+y2)2f(x,y) = (x^2 - y^2)/(x^2 + y^2)^2 on [0,1]2[0,1]^2, where iterated integrals are ±π/4\pm \pi/4.

Statement. If νμ\nu \ll \mu (absolutely continuous) and both are σ\sigma-finite, then there exists a measurable function f=dν/dμf = d\nu/d\mu such that ν(A)=Afdμ\nu(A) = \int_A f\,d\mu for all measurable AA. The function ff is unique almost everywhere.

Intuition. The Radon-Nikodym derivative generalises the idea of a density function from probability theory. For example, if ν\nu has density ff with respect to Lebesgue measure, then dν=fdxd\nu = f\,dx.

Application. Conditional expectation in probability theory: E[XF]E[X|\mathcal{F}] is defined as the Radon-Nikodym derivative dν/dPd\nu/dP where ν(A)=AXdP\nu(A) = \int_A X\,dP for AFA \in \mathcal{F}.

The convergence theorems (MCT, Fatou, DCT) form an interdependent chain: MCT implies Fatou, and Fatou plus a dominating function implies DCT. The inequalities (H”older, Minkowski) define the geometry of LpL^p spaces. Fubini connects product integration to iterated integration. Radon-Nikodym bridges absolute continuity and densities.

  1. Compute limn0sin(x/n)x(1+x2)dx\lim_{n\to\infty} \int_0^\infty \frac{\sin(x/n)}{x(1+x^2)}\,dx using DCT.
  2. Show that if fnff_n \to f in LpL^p then fnpfp\int |f_n|^p \to \int |f|^p. Give a counterexample where fnff_n \to f a.e. but fn↛f\int f_n \not\to \int f without a dominating function.
  3. Let fL1(R)f \in L^1(\mathbb{R}) and define F(x)=Rf(t)eixtdtF(x) = \int_{\mathbb{R}} f(t) e^{-ixt}\,dt. Show FF is continuous using DCT.
  4. Use H”older’s inequality to prove that if μ(X)<\mu(X) < \infty, then Lp(X)Lq(X)L^p(X) \subseteq L^q(X) for 1qp1 \leq q \leq p \leq \infty.
  5. Find a measurable function ff on [0,1]2[0,1]^2 such that 0101fdxdy0101fdydx\int_0^1 \int_0^1 f\,dx\,dy \neq \int_0^1 \int_0^1 f\,dy\,dx, and identify why Fubini’s theorem does not apply.

Measure theory provides rigorous foundations for integration. The convergence theorems (MCT, Fatou, DCT) govern when limits and integrals can be interchanged. H”older and Minkowski inequalities establish LpL^p space structure. Fubini’s theorem handles product measures, and the Radon-Nikodym theorem connects measures via densities.

ConceptDefinitionExample
σ\sigma-algebraCollection closed under complements and countable unionsBorel σ\sigma-algebra on R\mathbb{R}
MeasureCountably additive set functionLebesgue measure, counting measure
Measurable functionPreimage of Borel set is measurableContinuous functions, indicator functions
Almost everywhereProperty holds except on a null setf=gf = g a.e.
LpL^p space${f : \intf
Mode of convergenceDefinitionRelation to others
Pointwise a.e.fn(x)f(x)f_n(x) \to f(x) for almost every xxWeakest
Uniform$\sup_xf_n(x) - f(x)
LpL^pfnfp0\|f_n - f\|_p \to 0Implies convergence in measure
In measure$\mu{f_n - f
Weak LpL^pfngfg\int f_n g \to \int f g for all gLqg \in L^qWeakest of the LpL^p modes
InequalityStatementUse case
Chebyshev$\mu(f
Youngabap/p+bq/qab \leq a^p/p + b^q/qProving H”older
H”olderfg1fpgq\|fg\|_1 \leq \|f\|_p \|g\|_qDuality of LpL^p spaces
Minkowskif+gpfp+gp\|f+g\|_p \leq \|f\|_p + \|g\|_pTriangle inequality
Jensenϕ(f)ϕ(f)\phi(\int f) \leq \int \phi(f) for convex ϕ\phiEntropy inequalities